-16x^2+14x+102=0

Solution for -16x^2+14x+102=0 equation:

-16x^2+14x+102=0

a = -16; b = 14; c = +102;
Δ = b2-4ac
Δ = 142-4·(-16)·102
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-82}{2*-16}=\frac{-96}{-32}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+82}{2*-16}=\frac{68}{-32}
=-2+1/8
$